The Eladr Protocol is a decentralized, security and efficiency enhanced Web3 noSQL database powered by IPFS as the data storage layer https://ipfs.io/, and the Cardano block chain as the rewards token platform, https://cardano.org/. It provides a JSON based, IPFS layer 2 solution for data indexing and retrieval in an 'append only' file system built with open source Node.js API libraries.

The ELADR token was designed to incentivize and reward community members as a proof of contribution. Token holders are also granted access to EduLadder.com premium features as well as associated ELADR token enabled apps.

WHITE PAPER Buy Now Try BETA

Real Problems! Real Experts!

Watch related videos of your favorite subject.
Connect with students from different parts of the world.
See Our team
Wondering how we keep quality?
Got unsolved questions?

Vedic-maths-->View question

## Explain SutraPuranapuranabyham from vedic maths with example?

##### Explain Sutra Sankalana-vyavakalanabhyam from vedic maths with example?

Taged users:

Likes:
Be first to like this question

Dislikes:
Be first to dislike this question
Puranapuranabyham: By the completion or non-completion

Puranapuranabyham is the eighth sutra of Vedic mathematics. Its corollary is Antyayor Dasakepi.

Puranapuranabyham is used to simplify or solve algebra problems.

Example: Solve for x in the equation x3 + 6x2 + 11x + 6 = 0
Start by estimating simple quadratic equations that may be similar to the left hand side of this equation. Since this equation includes a cubed variable, incorporate cubing into the estimated quadratic equations. Look at the numbers that aren't variables in the problem: 1, 6, 11, and 6. So we know that if we cube a large number, our estimate will be way off. We also know that the cubed variable in the equation is multiplied by 1, and only 1. So we know the simple quadratic will be in the form of (x + __)3
estimate #1: (x + 1)3 We don't even have to work out the answer to know this is going to be too low. 1 cubed is still just 1.
estimate #2: (x + 2)3 This works out to x3 + 6x2 + 12x + 8
We'll stop there, because estimate #2 is very close to the equation we're solving.
Subtract from our estimated quadratic equation the left hand side of the problem, (x3 + 6x2 + 12x + 8) - (x3 + 6x2 + 11x + 6) = x + 2
So, add (x + 2) to both sides of the problem, which leaves us with x3 + 6x2 + 12x + 8 = x + 2
We can further simplify this as (x + 2)3 = (x + 2)
Now we have a common term, (x + 2), on both sides of the equation. Set up another variable, y, to equal (x + 2)
y3 = y
We can then infer that y must equal 0 or 1 or -1
If x + 2 = 0 then x = -2
If x + 2 = 1 then x = -1
If x + 2 = -1 then x = -3
Thus, x = -1,-2,-3

Likes:
Be first to like this answer

Dislikes:
Be first to dislike this answer