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I-ching-the-book-of-change-->View question

Asked On2019-04-09 13:36:23 by:Rohit498

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$B$ is correct here. It has probability $\frac{1}{2}$ in contrast to the other options that all have probability $\frac{1}{4}$.

A) TT has probability $\frac{1}{4}$

B) HT or TH has probability $\frac{1}{4}+\frac{1}{4}$ (summation of two probabilities of mutually exclusive events)

C) HH has probability $\frac{1}{4}$

D) HT has probability $\frac{1}{4}$

Essential for this conclusion is the fact that the coin is unbiased.

Answerd on:2019-05-17 Answerd By:rishabhshukla

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$B$ is correct here. It has probability $\frac{1}{2}$ in contrast to the other options that all have probability $\frac{1}{4}$.

A) TT has probability $\frac{1}{4}$

B) HT or TH has probability $\frac{1}{4}+\frac{1}{4}$ (summation of two probabilities of mutually exclusive events)

C) HH has probability $\frac{1}{4}$

D) HT has probability $\frac{1}{4}$

Essential for this conclusion is the fact that the coin is unbiased.

Answerd on:2019-05-17 Answerd By:rishabhshukla

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$B$ is correct here. It has probability $\frac{1}{2}$ in contrast to the other options that all have probability $\frac{1}{4}$.

A) TT has probability $\frac{1}{4}$

B) HT or TH has probability $\frac{1}{4}+\frac{1}{4}$ (summation of two probabilities of mutually exclusive events)

C) HH has probability $\frac{1}{4}$

D) HT has probability $\frac{1}{4}$

Essential for this conclusion is the fact that the coin is unbiased.

Answerd on:2019-05-17 Answerd By:rishabhshukla

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|rishabhshukla

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$B$ is correct here. It has probability $\frac{1}{2}$ in contrast to the other options that all have probability $\frac{1}{4}$.

A) TT has probability $\frac{1}{4}$

B) HT or TH has probability $\frac{1}{4}+\frac{1}{4}$ (summation of two probabilities of mutually exclusive events)

C) HH has probability $\frac{1}{4}$

D) HT has probability $\frac{1}{4}$

Essential for this conclusion is the fact that the coin is unbiased.

Answerd on:2019-05-17 Answerd By:rishabhshukla

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|rishabhshukla

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$B$ is correct here. It has probability $\frac{1}{2}$ in contrast to the other options that all have probability $\frac{1}{4}$.

A) TT has probability $\frac{1}{4}$

B) HT or TH has probability $\frac{1}{4}+\frac{1}{4}$ (summation of two probabilities of mutually exclusive events)

C) HH has probability $\frac{1}{4}$

D) HT has probability $\frac{1}{4}$

Essential for this conclusion is the fact that the coin is unbiased.

Answerd on:2019-05-17 Answerd By:rishabhshukla

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|rishabhshukla

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